b^2-11b-12=0

Solution for b^2-11b-12=0 equation:

Simplifying
b2 + -11b + -12 = 0

Reorder the terms:
-12 + -11b + b2 = 0

Solving
-12 + -11b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-1 + -1b)(12 + -1b) = 0

Subproblem 1
Set the factor '(-1 + -1b)' equal to zero and attempt to solve:

Simplifying
-1 + -1b = 0

Solving
-1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1b = 0 + 1
-1b = 0 + 1

Combine like terms: 0 + 1 = 1
-1b = 1

Divide each side by '-1'.
b = -1

Simplifying
b = -1
Subproblem 2
Set the factor '(12 + -1b)' equal to zero and attempt to solve:

Simplifying
12 + -1b = 0

Solving
12 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1b = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1b = 0 + -12
-1b = 0 + -12

Combine like terms: 0 + -12 = -12
-1b = -12

Divide each side by '-1'.
b = 12

Simplifying
b = 12
Solution
b = {-1, 12}